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PLEASE HELP find a third degree polynomial equation in standard form with rational coefficents that has the roots -5 and 6+i
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|dw:1418098175681:dw|
is what i have so far its just every time i multiply them together i get weird number so if someone could just multiply it out?
Start by multiplying the two factors with the imaginary numbers. \[(x-(6-i))(x-(6-i))\]\[x ^{2} -6x+x i-6x-6i+36-x i+6i-i ^{2}\]The xi and 6i cancel out. i^2 = -1 So we have this \[x ^{2}-12x+37\] Now multiply this by the other factor (x+5) \[(x+5)(x ^{2}-12x+37)\]\[x ^{3}-12x ^{2}+37x+5x ^{2}-60x+185\]\[x ^{3}-7x ^{2}-23x+185\]
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