Use the half angle formulas to simplify the expression. -sqrt ((1+cos 8x)/(1-cos 8x))
well can't you use \[\cos^2(4x) = \frac{1 + \cos(8x)}{2}~~~or~~~2\cos^2(4x) = 1 + \cos(8x)\] and \[\sin^2(4x) = \frac{1 - \cos(8x)}{2}~~~~or~~~~2\sin^2(4x) = 1 - \cos(8x)\] sustitute them and you have \[- \sqrt{\frac{2\cos^2(4x)}{2\sin^2(4x)}}\]
and then you should be able to work from there
how do you know theyre equal to that?
Not really Im so confused.
Yes, its the half angle one im confused with
Why would I be using the double angle formulas?
I have them I just dont know what to use
So I need to use double angle formulas and not the half angle ones?
ok where do i plug in the expression into the formula
i"ll eliminate all posts so that the information is in sequence... and see if it makes sense. and \[-\sqrt{\frac{2\cos^2(4x)}{2\sin^2(4x)}} = -\sqrt{\cot^2(4x)}\] just simplify from here
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