Question

Just wanted to see if this was right.

Solve in quadratic equation.

x^2 + 3x = 10
x^2 + 3x - 10 = 10 - 10
x^2 + 3x - 10 = 0
x + 5x - 2 = 0
x + 5 = 0 or x - 2 = 0
x = -5 or x = 2

If it's not please say where the mistake was made. Thanks so much.

Answer 1

x^2 +3x -10 = 0
x^2 +5x -2x -10 = 0
x(x+5) -2(x+5) = 0

Answer 2

that is correct.

Answer 3

x=-5 and x=2

Answer 4

Ok, Don't get it. That just gave me equation it gave me. But I needed two different answers for what x= ?.

I am. yay. Was all kinds of confused for a moment there. Thank you.

Answer 5

ok,

x (x+3) = 10
(x-2) (x+5) = 0 so x=2 and x=-5

Answer 6

But why would you write `x(x+3)=10` @felavin ?

Answer 7

Your first 3 steps seem to be fine, @bitesize007 , then i'm not sure how you got to x+5x-2=0

Answer 8

we have x^2 + 3x = 10 so x (x+3) = 10 and then:
(x-2) (x+5) = 0 so x=2 and x=-5

Answer 9

this is the fast way @Jhannybean

Answer 10

Should the 3 have stayed? I don't really know how it got turned into a 5 to be honest. Saw it down in the book to almost the same equation so just copied what it did in the book bu steps.

Answer 11

Just according to what you have written, up to the third step:

`x^2 +3x-10=0`

The 4th step you have written there looks wrong to me: `x+5x-2=0`

From the third step that you have there, I would go straight to factoring, that is, find two numbers that multiply to give `-10` and add to give `+3`

Answer 12

SO you have everything right, just remove that 4th step: `x+5x-2=0`you have written there.

Answer 13

Are you good? :)

Answer 14

Just remove the 4th step or remove all from there and rewrite it like this ?
x^2 + 3x - 2 = 0
x + 3 = 0 or x - 2= 0
x = -3 0r x = 2

Answer 15

Any case, just remove the 4th step you have written there and you will be fine.

Answer 16

Alright, Thanks for your help.