Evaluate. (I'll include the equation)
try first
let me see you attempt it with all of your knowledge
Hint: Convert the exponents into fractional form
well I tried but i got lost. first tho idk if i should multiply the two 5 square roots together by 3
laws of exponent
\[\frac{ \sqrt[3]{5}*\sqrt{5} }{ \sqrt[3]{5^5} }\] \[\frac{ x^{\frac{ 1 }{ 3 }} * x^{\frac{ 1 }{ 2 }} }{ (x^5)^{\frac{ 1 }{ 3} } }\] \[\frac{ x^{\frac{ 1 }{ 6 }} }{ (x)^{\frac{ 5 }{ 3} } }\]
I see. im gonna try to do it on my own then
hint: \[\huge \frac{ x^m }{ x^n } \implies x^{m-n}\]
well remember: \(\large \sf \sqrt[m]{x^n} = x^{n/m}\)
In this case your \(\sf m = 3 ~ , ~ n = 5\)
Here is my poor attempt at promoting my logarithm tutorial that has exponent laws: http://openstudy.com/users/iambatman#/updates/5403fdfde4b0f2ed1e14206a
:O even you make tutorials..
When I get bored lol
im thinking my answer is c .-.
Not sure how you got that, can you show your work please?
ya im lost now. I cant even understand how i calculated this
somehow i ended up with 0.26
\[\frac{ x ^{\frac{ 1 }{ 6 }} }{ x^{\frac{ 5 }{ 3 }} }\] \[x^{\frac{ 1 }{ 6 } - \frac{ 5 }{ 3 }} \]
wouldnt 0.26 be D?
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