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Suppose a binomial event has a probability of success of 0.1 and 750 trials are performed. What is the standard deviation of the possible outcomes?
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st.dev.=sqrt( n*p*(1-p) ) So you have p=0.1 and n=750 st.dev=sqrt( 750* 0.1*0.9)
uhh here is a more natural approach if u dont wanna believe in the formula yet
you know that in 1 standard deviation about 68% of the outcomes have to exist closed to the mean
oh wow that was actually a lot quicker than i thought, thanks, and yep
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