Question

In the figure, ABCD is a parallelogram. E and F are points on AD and BC resepctively such that AB//EF. EP meets AC at G. If AG:GC=1:2, then area of ABFG:area of EGCD=?
@Hero @Callisto @ganeshie8 @hartnn

Answer 1

lol not in scale :P

Answer 2

find ratio of areas of triangle AGE and FGC

Answer 3

1:4?

Answer 4

similar triangles...
and yes

Answer 5

how about ratio of areas of
ABFE : DCFE

Answer 6

1:2?

Answer 7

AE:FC is 1:2
right ?

Answer 8

yup

Answer 9

so ratio for areas is (1:2)^2
isn't it ?

Answer 10

the answer is 5:8 :O

Answer 11

@Callisto CE02 MC Q44 :'(

Answer 12

(1:1+2)^2 = (AG:AC)^2 = ratio of area of AGE : ACD = 1:9
Area of EGDC = 9-1 = 8

(2:1+2)^2 = (CG:AC)^2 = ratio of area of CGF : CAB = 4:9
Area of GFBA = 9-4 = 5

DONE!

Answer 13

wow let me digest it first

Answer 14

@Callisto what's the theorem??