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WILL GIVE MEDAL AND BECOME FAN. Express in the form of " a+bi " \[\large \bf \sqrt{i}+\sqrt{-i}\]
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\[\large \bf \sqrt{i}+\sqrt{-i}\]
@hartnn
let me try let a+bi = sqrt i + sqrt(-i) square both sides
a^2 - b^2 +2abi = i +i + 2sqrt (-i^2) (a^2-b^2 ) + (2ab)i = 2i + 2
compare real and imaginary parts ab =1 a^2-b^2 = 2 something seems wrong...
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a^2 - b^2 +2abi = i -i + 2sqrt (-i^2) (a^2-b^2 ) + (2ab)i = 0 + 2
yeah, so ab = 0 a^2-b^2 = 2 if b =0 , a^2 =2, s = sqrt 2
hence sqrt i + sqrt (-i) = sqrt 2 + 0i :)
ask if any doubt in any step
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oh!! thank you .. @hartnn
i got it
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