Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Given
sqrt ( x + 1) = 4
We raise both sides to power 2 in order to clear the square root.
[ sqrt ( x + 1) ] 2 = 4 2
and simplify
x + 1 = 16
Solve for x.
x = 15
NOTE: Since we squared both sides without putting any conditions, extraneous solutions may be introduced, checking the solutions is necessary.
Left side (LS) of the given equation when x = 15
LS = sqrt (x + 1) = sqrt (15 + 1) = 4
Right Side (RS) of the given equation when x = 15
RS = 4
For x = 15, the left and the rigth sides of the given equation are equal: x = 15 is a solution to the given equation.
Example 2 : Find all real solutions to the equation
OpenStudy (anonymous):
(x+1) is raised to four
OpenStudy (anonymous):
what was all that gibberish?
OpenStudy (anonymous):
the square root of something raised to the power of four is that something raised to the power of 2
OpenStudy (anonymous):
lol
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
can you make it clear?
OpenStudy (anonymous):
lol it broke it all down
OpenStudy (anonymous):
wait this is the given \[\sqrt{(x+1)^4} \]
OpenStudy (anonymous):
yeah my bad
OpenStudy (anonymous):
@No.name your real funny im trying to help her
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[\huge [(x+1)^2]^2\]
right?
OpenStudy (anonymous):
stop
OpenStudy (anonymous):
\[\sqrt{x^4}=x^2\\
\sqrt{(x+1)^4}=(x+1)^2\]
OpenStudy (anonymous):
so i was right
OpenStudy (anonymous):
thank you
Still Need Help?
Join the QuestionCove community and study together with friends!