Question

What is the refractive index of a medium when the light strikes the medium after traveling through air at an angle of 23.3° and the refracted angle is 14.6°?
A. 1.33
B. 1.36
C. 1.44
D. 1.57
E. 1.91

Answer 1

please apply the law of snell, namely:
\[n _{air}*\sin \theta _{1}=n _{medium}\sin \theta _{2}\]

Answer 2

Law of who now? also i don't have a calc.

Answer 3

law of Snell

Answer 4

please use Windows calc!

Answer 5

please note that your refractive index is equals to:
\[\frac{ m _{medium} }{ n _{air} }\]
referring to the formula that I wrote above

Answer 6

oops sorry:
\[\frac{ n _{medium} }{ n _{air} }\]

Answer 7

I don't understand what doesn n stand for and what is the medium?

Answer 8

@HarshTheAwesome

Answer 9

your refractive index is a relative refractive index respect with to air, it is equals to:
\[\frac{ n _{medium} }{ n _{air} }=\frac{ \sin \theta _{1} }{ \sin \theta _{2} }\]

Answer 10

The answer choices are weird

Answer 11

with:
\[\theta _{1}=23.3,\theta _{2}=14.6\]

Answer 12

My bad, it's 1.57

Answer 13

sin(23.3)/sin(14.6)

Answer 14

@Odette32691148 please try to substitute your numerica data in the formula above!

Answer 15

try please!
\[\frac{ n _{medium} }{ n _{air} }=\frac{ \sin(23.3) }{ \sin(14.6) }=...\]

Answer 16

use Windows calc, please!

Answer 17

select "scientific" view from menu, please!