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what is the integral of sec^5 x dx
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You need u-substitution for this one. When secx is to the odd power, you should automatically think: make u = ?
how can i do that? I have conflicts aboutthis opic
This info should be in the beginning of whatever chapter you're on or a past one if you've already covered it. You'll learn more if you try to find it on your own.
someone please help me.
\[\sec ^5x=\sec ^4x \sec x=\left( \sec ^2x \right)^2\sec x=\left( 1+\tan ^2x \right)^2\sec x\] now you can solve.
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thankyou
yw
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