Question

Will award medal, image attached

Answer 1

@ganeshie8

Answer 2

As a start : draw the region in xy plane

Answer 3

so what i learned in class is that the dydx stay the same for an expanded function, but it says its wrong

Answer 4

dydx and dxdy are the two ways you can mess with a double integral

Answer 5

right, and one might make the integral easier to evaluate

Answer 6

yes first one is easy already
but the second one requires you to split the integral if you see..

Answer 7

yea. but what would the integral be in term of first. ive tried what i think to be all posibilities

Answer 8

try this :

```
y : 0->3
x : y/3->y
```
```
y : 3->9
x : y/3->3
```

Answer 9

\[\int\limits_{0}^3 \int\limits_{y/3}^y f(x,y) dxdy + \int\limits_{3}^9 \int\limits_{y/3}^3 f(x,y) dxdy \]

Answer 10

yea that worked. i guess it will only tell you if it is correct if you fill in all of the values

Answer 11

did you get why they worked

Answer 12

for the second double integral, what was the reasoning behind finding those bounds.

Answer 13

sketch the triangle in xy plane

Answer 14

http://gyazo.com/135d269f1c9a29dda25cf62754d4ae55

Answer 15

blue region is for first double integral and red region is for the second double integral

Answer 16

oh wow that makes it much more clear, thanks

Answer 17

\[\color{blue}{\int\limits_{0}^3 \int\limits_{y/3}^y f(x,y) dxdy} + \color{red}{\int\limits_{3}^9 \int\limits_{y/3}^3 f(x,y) dxdy}\]

Answer 18

you need to sketch the region to setup the bounds