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Mathematics 15 Online
OpenStudy (darkbluechocobo):

Help with Log Models

OpenStudy (darkbluechocobo):

OpenStudy (xapproachesinfinity):

what I'm wondering about is how to get such model for such experiments hehe

OpenStudy (anonymous):

\[t(p) =\frac{ \ln (\frac{ p }{ 100 }) }{ 0.02 }\] \[t(p) = \frac{ \ln{ (p )}- \ln (100 ) }{ 0.02 }\] \[500 = \frac{ \ln{ (p )}- \ln (100 ) }{ 0.02 }\]

ganeshie8 (ganeshie8):

that was just an exponential growth formula @xapproachesinfinity

OpenStudy (xapproachesinfinity):

to answer your question replace p by 500

ganeshie8 (ganeshie8):

hey just plugin p=500

OpenStudy (xapproachesinfinity):

you are looking for times here t p is our independent variable

OpenStudy (darkbluechocobo):

so ln(500)-ln(100)/0.02

ganeshie8 (ganeshie8):

why not simply divide 500/100 = 5 ?

OpenStudy (xapproachesinfinity):

@ganeshie8 so if we reversed it (inverse) we would get the growth of population with time but do flowers grow that fast

ganeshie8 (ganeshie8):

maybe they are wild flowers growing crazily :P

OpenStudy (darkbluechocobo):

so would that mean 5/0.02

OpenStudy (darkbluechocobo):

or ln(5)?

ganeshie8 (ganeshie8):

dont forget that 500/100 is wrapped by ln

OpenStudy (darkbluechocobo):

80.5 would be the answer den

OpenStudy (xapproachesinfinity):

hehehe that must be the case otherwise it wouldn't make any sense! this is some imaginary experiment lol

OpenStudy (xapproachesinfinity):

this model business is something that i don't get sometimes hehe especially if it's polynomials. i would like you @ganeshie8 to explain it some other times if you may ^_^

ganeshie8 (ganeshie8):

I think these fall under statistics/regression... @Marki knows these better than me :)

OpenStudy (anonymous):

?

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