Question

what is the total heat that must be added to convert the 80g of ice at -20 degrees Celsius to water at 25 degrees Celsius?

Answer 1

You have to break up the problem into 3 steps:

1. Heating ice from -20 to 0 celsius: \(\large q_1=m*C^{ice}_p*\Delta T\)

2. Melting ice: \(\large q_2=m*\Delta H_{fusion}\)

3. Heating water from 0 to 25 celsius: \(\large q_3=m*C^{water}_p*\Delta T\)




\(\huge q_{total}=q_1+q_2+q_3\)