An airplane flies 200 km east from City A to City B, then 200 km south from city B to city C and finally 100 km northwest to city D. How far is it from city A to city D? In what direction must the airplane head to return directly to city A from city D?
Is this a multiple choice question? if so can you give me the answer choices? if its not, Im working on the answer for this one :)
its not multiple choice .. its a problem solving .
Alright, Im not sure if I'll be much help, but I think the answer to is Use pythagorean theorem h= the square toot of 200^2 + 200^2. = 282.84Km. then substract 100km = 182.84 direction: To return from city d to city a it has to keep going west of north. or Northwest, since its a 45 angle.
so I think the answer is 100. but you might want to check my work and make sure I didn't make any errors.
I think that graph below describes your situation, please: |dw:1418162797820:dw| do you agree?
@acsahmanuel26
thank you so much :D
what is the length of segment AB?
sorry, what is the length of segment AC?
no, sorry, it is half diagonal of the square whose side is 200 km, namely: |dw:1418163286154:dw|
so I have to apply theorem of Pitagora, namely: \[AC=\sqrt{200^{2}+200^{2}}=200*1.41=282 km\] do you agree?
@acsahmanuel26 do you know theorem of Pitagora?
yeah c2=a2+b2
ok! so AC=282 km, do you agree?
is the distance from segment ac is 282.84?
that's right!
thank you.. so the distance from city a to city d is 282.84 km?
now please note that: |dw:1418163765772:dw|
182 km?
no, please note my drawing, you are at D and DC=100 km. Now you know thatAC=282 km, so we can write: \[x+100=282.84\] where x =distance AD, so?
then x=282.82-100=...
x=182 km, you are right! congratulations!
thank you so much... and the direction is northwest?
that's right!
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