If f(x) varies directly with x2, and f(x) = 72 when x = 6, find the value of f(3) Help?
f(3) means when x = 3
72 = 2x
Nope
Would it be 18
@adamaero
for x = 3 or x = 6? but actually I think I read the problem too fast, I lead you down the wrong path... let me check...
x=6. I think.
I'm just generally confused about this entire thing lol.
are you sure it's not x^2 ?
Oh, sh** lol. I forgot to put the little ^. Yes, it's x^2. Sorry about that.. haha
lol, you can't swear on here anyways flutter that feather
I know haha, I've tried it before.
wio's already on the way answering it for you: http://openstudy.com/study#/updates/54877db4e4b0c0f1a1527fc0
here is someone else answering it for you: http://openstudy.com/study#/updates/54877e6be4b0c0f1a1528099
Oh. Okay. Thanks so much lol
@Chelleyhi are you there?
\[f(x)=kx^2 \] this is the first translation you should get
now we can find the constant k given the second sentence the second sentence says we have f(x)=72 when x=6 so we have 72=k(6)^2
solving that for k gives us what?
18?
72/36= is that 18
let me think 72/36=2
isn't it?
since 36+36=72 there are 2(36)=72 so 2=72/36
\[f(x)=kx^2 \\ \text{ so k is 2} \\ f(x)=2x^2 \]
now just plug in 3 to find f(3)
f(3)=2(3)^2
oh do you mean f(3)=18 if so yes
since 2*3^2=2*9=18
Thank you for your help, I did a bunch of googling and finally figured out how to do it.
Good job you! :)
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