Question

Help with portions of lines please?!?!

Answer 1

what you got?

Answer 2

Point C is located at (1, 2) and point D is located at (-4, -2). Find the point that is the distance from point C to point D

Answer 3

This is just an example. Every time I do one of these I get it wrong

Answer 4

half way between? take the average in each coordinate

Answer 5

the math way to write it is \(\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\) but it is just the average

Answer 6

there may be a typo in your question, not sure
but half was in your example is \\[\left(-\frac{3}{2},0\right)\]

Answer 7

Okay. So how would you find 3:5 of a line? Like after you find the length of the line?

Answer 8

can you post the exact question?

Answer 9

Sure. One moment

Answer 10

Find the point I such that DI and EI form a 3:5 ratio
https://courses.vlacs.org/file.php/2221/58985_51dc5798/0600_g11_q3.jpg

Answer 11

from -1 to 4 is 5 units
from -1 to 2 is 3 units

Answer 12

link did not work
from -2 to 2 is 4 units

Answer 13

The points are at (-3,2) and (5,5)

Answer 14

from -3 to 5 is 8 units
\(\frac{3}{5}\times 8=\frac{24}{5}\) and \(-3+\frac{24}{5}=1\tfrac{4}{5}=1.8\) for the first coordinate

Answer 15

second one is similar

Answer 16

That isn't how I was taught to do it and 1.8 isn't a choice. The way I learned was to use the distance formula to find the distance of the line, and then figure it out from there...