Question

ln^3radical33 and ln3=a ln11=b

Answer 1

This is hard for me to understand.

Answer 2

do you mean \[\ln(\sqrt[3]{33}) \\ \ln(3)=a \\ \ln(11)=b \]?
what do you want to do with this exactly though?

Answer 3

do you want to write the first line in terms of a and b?

Answer 4

if so recall that \[\sqrt[a]{x^b}=x^\frac{b}{a}\]

Answer 5

then use power rule for log

Answer 6

then use product rule for log

Answer 7

sorry this is what its asking me. Suppose that ln3=a and ln11=b. use properties of logarithms to write the logarithm in terms of a and b. ln^3radical33

Answer 8

\[\sqrt[3]{33}=33^\frac{1}{3} \\ \text{ so you have } \\ \ln(33^\frac{1}{3})\]
and what I'm saying is you can use power rule there

Answer 9

bring down the exponent in front
that is power rule
ln(x^r)=rln(x)

Answer 10

\[\ln([f \cdot g]^r)=r \ln(f \cdot g) \text{ by power rule } \\ =r [\ln(f)+\ln(g)] \text{ by product rule }\]

Answer 11

these are exactly the steps you need to take

Answer 12

realize that you can use 33=3*11 somewhere

Answer 13

so the answer would be 1/2ln(33^1/3)??

Answer 14

I still need help. i still dont get it