Question

Find the area enclosed by the curve (see photo):

I think my set-up is wrong. I didn't get the answer I was supposed to get.

Answer 1

Hint: the integration is correct, but the question asks for the area enclosed by the curve,
A simple integration will negate the part below the x-axis.
Subdivide the integral into three intervals and add the areas (all positive) and see if you get the right answer.

Answer 2

Do you think you can just type out the equation for me, please? I'm just short on time. Normally I would do it myself and fiddle around with the equation, to see if I got the answer, but I don't have time right now. Thank You!

Answer 3

I indicated the zeroes of f(x), so your integrals should look like:
\(\int_0^{\pi/3}f(x)dx - \int_{\pi/3}^{2\pi/3}f(x)dx + \int_{2\pi/3}^{3}f(x)dx\)
and \(f(x)=sin(3x)\)

Answer 4

Thank you, @mathmate!

Answer 5

no problem!
:)