Question

2yx^0 is this whole thing become 1 then cancel out or just the x??????

Answer 1

if the 0 is just an exponent for x, then x^0 = 1

the 2y doesn't change

Answer 2

if you had (2yx)^0, then the whole thing would be 1

Answer 3

alright thanks and btw it wasnt in parentheses so yea

Answer 4

ok, then it's 2y

Answer 5

alright what would happen next if it was (2yx^0 . x^3 y^2/2x^3 y^-2)-2

Answer 6

The problem is this right?
\[\Large \left(\frac{2yx^0*x^3y^2}{2x^3y^{-2}}\right)^{-2}\]

Answer 7

yes lol

Answer 8

what do you get when you simplify the numerator?

Answer 9

2y .x^3 y^2

Answer 10

what is y times y^2 equal to?

Answer 11

y^3

Answer 12

good

Answer 13

we now have
\[\Large \left(\frac{2x^3y^3}{2x^3y^{-2}}\right)^{-2}\]

Answer 14

now try to simplify the fraction inside the parenthesis (ignore the negative -2 exponent on the very outside)

Answer 15

would it be 1y^5?

Answer 16

or just y^5

Answer 17

good,

\[\Large \left(\frac{2x^3y^3}{2x^3y^{-2}}\right)^{-2} = (y^5)^{-2}\]

Answer 18

when you raise an exponential expression to another exponent, you multiply the exponents

Answer 19

so -25? but wouldnt u flip the equation because its a negative exponent?

Answer 20

5 times -2 is not -25

Answer 21

(1/y^5)^2

Answer 22

yes you did a valid move, so,

\[\Large \left(\frac{1}{y^5}\right)^{2} = \frac{1^2}{(y^5)^2} = \frac{1}{y^{10}}\]

Answer 23

be careful and notice how I got 10 as the exponent and NOT 25

Answer 24

you're tempted to say 5^2 = 25

but it should be 5*2 = 10

Answer 25

yea lol

Answer 26

4^b-3=64 idk how to do this apparently i have to make it something like 4^b-3=4^4?

Answer 27

b-3 is the exponent?

Answer 28

yes