@HELP_ME! f(x)=5/x^3 find the antiderivative
\[\Large\rm f(x)=\frac{5}{x^3}\]If we use an exponent rule, we can write our function like this,\[\Large\rm f(x)=5x^{-3}\]This allows us to more easily apply our power rule.
Errr.. power rule for integration, whatever you want to call it :)
ok so far so good :)
So we're using the fact that the antiderivative of \(\Large\rm x^n\) is \(\Large\rm \frac{1}{n+1}x^{n+1}\)
use \[\Large \int x^ndx = \frac{1}{n+1}x^{n+1}+C\]
Power increases by 1, then divide by that new power.
so when the power increases in become -4 right?
Ah! So it's easy to get tripped up when we're dealing with negative numbers. So our power will become -3+1
ok so its -2 then
Mmm looks good
so.. 5x^-2/-2 +c?
Good good good. It might be a good idea to put it back into the form that it was given to you in:\[\Large\rm -\frac{5}{2x^{2}}+c\]
correct, \[\Large -\frac{5}{2}x^{-2} + C\]
Not a big deal though :)
@zepdrix yea my textbook answer puts it back into the form it was given but im glad its still correct lol
thank you both
np
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