Join the QuestionCove community and study together with friends!
Sign Up
zepdrix (zepdrix):
\[\Large\rm f(x)=\frac{5}{x^3}\]If we use an exponent rule, we can write our function like this,\[\Large\rm f(x)=5x^{-3}\]This allows us to more easily apply our power rule.
zepdrix (zepdrix):
Errr.. power rule for integration, whatever you want to call it :)
OpenStudy (anonymous):
ok so far so good :)
zepdrix (zepdrix):
So we're using the fact that the antiderivative of \(\Large\rm x^n\) is \(\Large\rm \frac{1}{n+1}x^{n+1}\)
jimthompson5910 (jim_thompson5910):
use
\[\Large \int x^ndx = \frac{1}{n+1}x^{n+1}+C\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
zepdrix (zepdrix):
Power increases by 1,
then divide by that new power.
OpenStudy (anonymous):
so when the power increases in become -4 right?
zepdrix (zepdrix):
Ah! So it's easy to get tripped up when we're dealing with negative numbers.
So our power will become -3+1
OpenStudy (anonymous):
ok so its -2 then
zepdrix (zepdrix):
Mmm looks good
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so.. 5x^-2/-2 +c?
zepdrix (zepdrix):
Good good good.
It might be a good idea to put it back into the form that it was given to you in:\[\Large\rm -\frac{5}{2x^{2}}+c\]
jimthompson5910 (jim_thompson5910):
correct,
\[\Large -\frac{5}{2}x^{-2} + C\]
zepdrix (zepdrix):
Not a big deal though :)
OpenStudy (anonymous):
@zepdrix yea my textbook answer puts it back into the form it was given but im glad its still correct lol
Still Need Help?
Join the QuestionCove community and study together with friends!