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Mathematics 22 Online
OpenStudy (anonymous):

HEY CAN SOMEONE HELP ME WITH ALGEBRA???!!! WILL MEDAL AND FAN!!! Find the ratio of a to b: http://static.k12.com/eli/ecollege/543/6_29448/2_30727_2_29450/b0f0ead74948683cdb0d44cf4717b5488f489500/media/6634f2493153b8ddaaa6941a68b8d5a306e5d2df/mathml_43555676d29ab709532580814d57325ee2f6d822_1.gif

OpenStudy (anonymous):

question?

OpenStudy (anonymous):

it is in the link

OpenStudy (anonymous):

here's a file

OpenStudy (anonymous):

choices?

OpenStudy (anonymous):

14a=3b a choice? if not, sorry cant help, goodluck

OpenStudy (anonymous):

no there is no multiple choice :/

OpenStudy (anonymous):

\[9(a+b)=51a\] is a start

OpenStudy (anonymous):

He got that from cross-multiply, just so you know

OpenStudy (anonymous):

then maybe \[9a+9b=51a\] or \[9b=42a\]

OpenStudy (anonymous):

if you want the ratio of \(a\) to \(b\) then \[\frac{a}{b}=\frac{9}{42}\] which reduces

OpenStudy (anonymous):

so the ratio from a to b is 9/42? @satellite73

OpenStudy (anonymous):

reduce the fraction

OpenStudy (anonymous):

so it's 3/14 @satellite73?

OpenStudy (anonymous):

looks good to me

OpenStudy (anonymous):

thanks so much @satellite73 :)

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