HEY CAN SOMEONE HELP ME WITH ALGEBRA???!!!
WILL MEDAL AND FAN!!!
Find the ratio of a to b:
http://static.k12.com/eli/ecollege/543/6_29448/2_30727_2_29450/b0f0ead74948683cdb0d44cf4717b5488f489500/media/6634f2493153b8ddaaa6941a68b8d5a306e5d2df/mathml_43555676d29ab709532580814d57325ee2f6d822_1.gif
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
question?
OpenStudy (anonymous):
it is in the link
OpenStudy (anonymous):
here's a file
OpenStudy (anonymous):
choices?
OpenStudy (anonymous):
14a=3b a choice? if not, sorry cant help, goodluck
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no there is no multiple choice :/
OpenStudy (anonymous):
\[9(a+b)=51a\] is a start
OpenStudy (anonymous):
He got that from cross-multiply, just so you know
OpenStudy (anonymous):
then maybe
\[9a+9b=51a\] or
\[9b=42a\]
OpenStudy (anonymous):
if you want the ratio of \(a\) to \(b\) then \[\frac{a}{b}=\frac{9}{42}\] which reduces
Still Need Help?
Join the QuestionCove community and study together with friends!