Question

check my math please
find the first and 2nd derivative of y=2/x^4 -^3sqrt(x)

Answer 1

\[y=2/(x^4) -\sqrt[3]{x}\]

Answer 2

for the first derivative i got -8x^-5 - 1/3 ^-2/3

Answer 3

so it would be -8/x^5 - 1/3x^2/3

Answer 4

and for the second derivative test i got 40/x^6 + 2/9x^5/3

Answer 5

This is what I calculated. Let me check it again to make sure.
\[y = ( 40/x^{6}) + (1/3\sqrt[3]{x ^{5}})\]

Answer 6

Nope. You're right. It is (2/9)x^5/3

Answer 7

i think u forgot to multiply the exponent -2/3 to -1/3x

Answer 8

but thanks though :D

Answer 9

No worries man :)