If 100mg of CuO is mixed with 1mL of 1M H2SO4, how much CuSO4 can be formed (in moles)

Question

abb0t · Answer

The first step is to write down the chemistry and show what is happening! ALWAYS. And make sure that the equation is written down $\sf \color{red}{balanced}$.

anonymous · Answer

CuO + H2SO4 --> CuSO4 + H2O

jhannybean · Answer

Copper (II) oxide mixed with sulfuric acid $$\sf CuO(s) + H_2SO_4 (aq) \to CuSO_4(aq) +H_2O(l)$$

balanced?

jhannybean · Answer

If it's balanced properly, this will help you in your mole-to-mole ratio in using copper(II) oxide to find the number of moles of copper(II)sulfate,

jhannybean · Answer

Since you are given 100 mg of copper(II) oxide, you want to change that to grams first. $$\sf 100 ~\text{mg} \times \frac{10^{-3} ~\text{g}}{1~\text{mg}} = ~?$$

jhannybean · Answer

Then use the amount of grams to convert from
$$\text{grams}\to \text{molar mass} \to \text{mole to mole ratio}$$To find the # of moles of $\sf CuSO_4$

abb0t · Answer

Wrong.