Question

@Kainui

Answer 1

A perfectly black body at 100°C emits light of intensity R(lambda) that has the strongest intensity near wavelength λo. The temperature of this body is now increased to 200°C. In terms of λo, near what wavelength does light radiated from this hotter body have the strongest intensity?

Answer 2

The formulas I'd say would be \[I = \sigma T^4\] and \[\lambda _{\max} T = 2.898 \times 10^{-3} mK\]

Answer 3

Actually there's two parts, here's the first: In terms of I, what is the intensity at which this hotter body radiates?

Answer 4

So for the first part I'm thinking it will have to make it into a fraction or something, I'm not entirely sure, so \[\frac{ I(200) }{ I(100) }\] ?

Answer 5

What do all these variables represent? I'll get you started, for instance λmax is the wavelength at which you see the strongest radiation, so in this case λo is λmax.

Answer 6

The wavelength is the peak wavelength, T = temperature, sigma is a constant, I is the intensity. And the reason I was doing a ratio is because you need a comparison for which the hotter body radiates.

Answer 7

Oh I guess I have to convert degrees into kelvin then.

Answer 8

I think I can see how to get part 1 then since I just had to convert it to kelvins haha, and for part b, would it be similar using but using Wien's displacement law making a ratio?

Answer 9

Sounds about right to me.