find the exact value of the expression. do not use a calculator
sin (-4pi) + cos (2pi)
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OpenStudy (anonymous):
well do you know the unit circle?
OpenStudy (princeharryyy):
welll d answer is 1 sin(2*2pi) = 0 and cos2pi = cos0 =1, and so the answer is 0 + 1 =1
OpenStudy (princeharryyy):
@lonakkkk
OpenStudy (anonymous):
@tejasvir is his method correct i would say im familiar with it and thanks @princeharryyy are u 100 percent sure
OpenStudy (anonymous):
i would say its -1
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OpenStudy (anonymous):
can i ask why?
OpenStudy (anonymous):
@tejasvir
OpenStudy (princeharryyy):
yes I am @lonakkkk
OpenStudy (princeharryyy):
these two function sure periodic 100% sure . check by plugging in your answers
OpenStudy (princeharryyy):
1 is d answer
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OpenStudy (anonymous):
will you help me with the new one i just posted and explain it to me @princeharryyy
OpenStudy (triciaal):
sin(2*2pi) are you sure this is the same as (-2*2pi) the original had (-4pi)
OpenStudy (princeharryyy):
yup it does not matter whether it is -4pi or 4pie whenever it is a product of an integer and pie in case of sin it is always zero (but, remember integer not the fraction) @triciaal