@Hoslos @Nurali @TylerD I dont even know how to do it. Population of a city. The population of a certain city was 112,000 in 1998, and the observed relative growth rate is 4% per year. (a) Find the function that models the population after t years. (b) find the projected population in the year 2004. (c) in what year will the population reach 200,000?
@Hoslos hey
@TylerD hey
@triciaal @abb0t @appleduardo know how to do it
@sammixboo @dan815 know how to do it
@uri please help me pplz
@ShelbyRenaebb @Algorithmic help me
@uri come back
@appleduardo the last part mostly
@triciaal can u help
its the same formula, dP/dt = kP, but in this case we know k which 4%, and we represent it with: dP/dt=0.04P
now you do the integration, and apply your limits and your done
i am reading the question
@sammixboo can u help
@appleduardo im not getting 2008
@ShelbyRenaebb i need help pplz
@triciaal for part c im not getting 2008
(a) Find the function that models the population after t years. f(t) = 0.04t + 112000
Is this trig? Or what?
@ShelbyRenaebb pre-calculus
Yeah ive only took algebra 2 and geometry. Not there yet im sorry D: Do you go to connections?
i saw this on differential equations lol
(b) find the projected population in the year 2004. start 1998 now 2004 how many years past? this is t find f(t) with with value
@ShelbyRenaebb i can do this; but this problem threw me off. im n college
@triciaal is it 8 or 9 im not sure
You can use geometric progression formula. Nth:ar ^n-1, therefore, after n years, it will be 112000*0.04^t-1
@triciaal my modeled equation is n(t)=112000e^0.04t
For b), it will be 112000 i0.04^(2004-1998)-1
@triciaal my t for part c is approximately 14. it does not equal 2008 if u add 14+1998
@triciaal what i do wrong
@triciaal it doesnt equal 2008
@Hoslos i used n(t)=112000e^0.04t
@klog23 https://www.youtube.com/watch?v=mhO9eL9Nuz0 check this out man, im pretty sure ull understand more quickly
(c) in what year will the population reach 200,000? this means f(t) = 200000 set 0.04t + 112000 = 200000
sorry its not linear its exponential
@triciaal is my equation correct i used n(t)=112000e^0.04t
For c), make t subject of the formula in 200000=112000*0.04^t-1
@Hoslos im not using geometric progression im using exponentials
I thought that formula is also an exponential one.
@Hoslos our professor doesnt use that
Ok.
oh i got it the answer is 14 and its 2013 not 2008
great 14.495 so round up since it would be in the next year 1998 + 15 = 2013
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