Question

sin^2x=2sinx+3 The answer is A+Bkpi where k is any integer

Answer 1

I assume they want us to solve for x. We need to get all terms on the same side first
Any ideas on how to do that? @KDubs

Answer 2

No they want us to solve for A and B

Answer 3

@uri

Answer 4

We use algebra to move terms to either side of the equals sign.
I would move the right terms to the left side of the equals sign
So since we start with +2sinx, we can do -2sinx on both sides to move it
How do you think we move the 3?

Answer 5

Right so we solve for x
It's x = A + Bkpi
You need to solve for x to find A and B

Answer 6

Wouldn't you just subtract the 3 to bring it to the other side @uri

Answer 7

Yes

Answer 8

So the. I'm confused on how you would get A and B

Answer 9

@uri

Answer 10

sin^2x=2sinx+3

sin^2 (x) - 2sin(x) -3 = 0

this is a quadratic in sin x

(sin x -3 ) ( sin x + 1) = 0

set the factors equal to zero

sin x = 3 , no solution

sin x = -1 , this gives us x = 3pi/2 , and you can add multiples of 2pi*k

x = 3pi/2 + 2*k*pi