Question

If k is a constant such that \(x^{3}+4x^{2}+kx-12\) is divisible by x+3, then k=?

Answer 1

just plug in x =-3
and equate it to 0

Answer 2

if x+3 is a factor then, x =-3 is a root

Answer 3

i got 1 but it's not correct :O

Answer 4

(-3)^3+4^2-3k−12 = 0

Answer 5

what is that 4^2 doing there

Answer 6

can you please verify your question again /

Answer 7

is it x^2 and not 4^2

Answer 8

if it is x^2
i got k =-10

Answer 9

4x^2

Answer 10

\(x^3+4x^2 +kx -12 =0, for \: x = -3\)

i got x=-1 too

Answer 11

k =-1

Answer 12

how did you get +1
?

Answer 13

:O
-3+k(-3)=0
....
oh i got it :O

Answer 14

excellent! :)

Answer 15

thanks :D