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Mathematics 13 Online
OpenStudy (anonymous):

The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2. How many moles of CO2 are produced when 35.0 mol C2H2 react completely? How do you get 35.0 mol out of C2H2?

OpenStudy (m3ga-bit3):

@ganeshie8

OpenStudy (m3ga-bit3):

he might be able to help you b cuz i have no idea:(sry

OpenStudy (perl):

first lets make the equation of reaction

OpenStudy (perl):

C2H2 + O2 ---> CO2 + H2O I believe

OpenStudy (anonymous):

2C2H2 + 5O2 -->4CO2 + 2H2O

OpenStudy (anonymous):

There is the equation

OpenStudy (perl):

is that balanced

OpenStudy (anonymous):

I would think thats what it shows in the question

OpenStudy (perl):

you can check that it is balanced by adding up the Carbons on the left side, equals to carbons on the right side, etc

OpenStudy (anonymous):

I'm very new to this

OpenStudy (perl):

ok so now lets answer the question

OpenStudy (anonymous):

ok

OpenStudy (perl):

2C2H2 + 5O2 -->4CO2 + 2H2O The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2. How many moles of CO2 are produced when 35.0 mol C2H2 react completely? How do you get 35.0 mol out of C2H2? 35 mol C2H2 * 26.04 grams / mol C2H2 , that will give you the grams of C2H2

OpenStudy (perl):

I am using this calculator http://www.lenntech.com/calculators/molecular/molecular-weight-calculator.htm plug in C2H2

OpenStudy (anonymous):

ok, and here is the problem for you http://prntscr.com/5f8a6o

OpenStudy (perl):

also you have 84 mol O2 * 32 g / mol O2 = 2688 grams O2

OpenStudy (perl):

and we have 35 mol C2H2 * 26.04 grams / mol C2H2 = 911.4 grams C2H2

OpenStudy (perl):

now we need to use stoichiometry, which means we can think of the balanced chemical equation as a mole equation 2 moles of C2H2 + 5 moles of O2 -->4 moles of CO2 + 2 moles H2O

OpenStudy (perl):

this says for every 2 moles of C2H2 there is 4 moles of CO2

OpenStudy (anonymous):

and for every 5 moles of O2 is 2 Moles of H20?

OpenStudy (perl):

yes that too

OpenStudy (perl):

ok and do you see how we got 911.4 grams C2H2 2688 grams of O2

OpenStudy (anonymous):

How do we setup the equation to get our mols of CO2

OpenStudy (perl):

The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2. How many moles of CO2 are produced when 35.0 mol C2H2 react completely? How do you get 35.0 mol out of C2H2? 35 moles of C2H2 * 4 mol CO2 / 2 mol C2H2 =

OpenStudy (perl):

so i multiplied 35 moles by the ratio 4moles CO2 for every 2 moles C2H2

OpenStudy (perl):

notice that the C2H2 cancels

OpenStudy (anonymous):

All units should cancel right? Leaving you with CO2

OpenStudy (anonymous):

70.0 mol of CO2

OpenStudy (perl):

correct

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