Question

HELPPPPPPPPPPP <3
I GIVE MEDALS
LOG 2 (x) + log 2 (x-1) = log 2 (2x - 3) + 1

Answer 1

log a +log b =log (axb)
this is one of the property in log's

Answer 2

@gibbs

Answer 3

@Walkerman15 @Here_to_Help15

Answer 4

@sammixboo @samson245 @KamiBug @jordanloveangel @joejoe213 @henrry123 @AndrewTheCookie @appleduardo

Answer 5

@chefducky

Answer 6

go to mathway .com

Answer 7

@CausticSyndicalist

Answer 8

@mathmate

Answer 9

@bibby

Answer 10

i have no clue

Answer 11

thanks :(

Answer 12

sorry

Answer 13

@myininaya

Answer 14

have you tried mathway.com

Answer 15

yes, it gives the answer but not the explanation

Answer 16

@iambatman

Answer 17

oh

Answer 18

@paki

Answer 19

if you apply the log rule log(a) + log(b) = log(ab) to the left hand side, then subtract log2(2x-3) from both sides, then apply log(a) - log(b) = log(a/b) to the left hand side again, I think you are looking at something like: log2 ((x^2-x)/(2x-3)) = 1.

Then, I think you can apply logbM =c ---> b^c = M, to rewrite like whole things like:
2^((x^2-x)/(2x-3)) = 2^1. Then since they have the same base, you can just solve what the base is raised to, right? So at the end you are just looking to solve ((x^2-x)/(2x-3)) = 1. You should def. double check my reasoning, but I'll leave the remaining work to you.

Answer 20

@celin3 i would go with @Ajk