Question

I WILL FAN AND MEDAL

Factor 9x^6 – 16y^6 completely.

First factor each term.
9x^6 = (__)^2
16y^6 = (__)^2

Then use a^2 – b^2 = (a – b)(a + b). Show your work.

9x^6 – 16y^6 =

Answer 1

First factor each term. 9x^6 = (3x^3)^2
16y^6 = (4y^3)^2

See if you agree with this.

Answer 2

yes i do @Directrix

Answer 3

9x^6 – 16y^6 = ( 3x^3 + 4y^3) ( 3x^3 - 4y^3)

How about this ^^. It is the difference of two squares just like a^2 - b^2 = (a + b)(a - b)

Answer 4

Yes thats what i got for the final answer. is that correct?

Answer 5

Based on the instructions, I think that this is all. The sum and difference of two cubes will factor but I don't think you are being asked to do that here.

Answer 6

okay @Directrix thanks so much

Answer 7

I am going to add a little work. Just a second.

Answer 8

9x^6 – 16y^6 = [(3x^3)]^2 - [(4y^3)]^2 --> add this step in your factoring

= ( 3x^3 + 4y^3) ( 3x^3 - 4y^3)

I think they want it set out like this. @madison.bush


That approach explains the reason you were asked to do this:

9x^6 = (__)^2 16y^6 = (__)^2

Answer 9

@Directrix okay yeah that makes sense. Thank you!

Answer 10

Add that step. Alrighty, then.

Answer 11

You're welcome. I'll see you around here on OS.