Mathematics
17 Online
OpenStudy (peterg2001):
please help
A gift basket has 2 pounds of cookies, 3/5 pound of fudge, and 1 1/4pounds of nuts. What is the total weight of the items in the basket?
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OpenStudy (peterg2001):
@AlexandervonHumboldt2
OpenStudy (alexandervonhumboldt2):
2+3/5+11/4=5 7/20
OpenStudy (peterg2001):
the answer is 3 17/20?
OpenStudy (anonymous):
yes it is 3(17/20)
OpenStudy (alexandervonhumboldt2):
no 5 7/20
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OpenStudy (peterg2001):
wrong
OpenStudy (anonymous):
If you don't believe me type it into your calculator and double check
OpenStudy (anonymous):
but just for you I will work it out
OpenStudy (anonymous):
so first we find the least common denominator between 5 and 4 which in this case is 20
OpenStudy (alexandervonhumboldt2):
2+12/20+55/20=(40+12+55)/20=107/20=5 7/20
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OpenStudy (anonymous):
and so we multiply so that each fraction is divided by 20
OpenStudy (peterg2001):
could be but i dont have that
14 3/4
-14 3/4
88 3/4
88 11/12
OpenStudy (peterg2001):
@AlexandervonHumboldt2
OpenStudy (alexandervonhumboldt2):
i dont know i have a calculator and it says 5 7/20
OpenStudy (anonymous):
2*20= 40 so we have
40/20
4*5=20 so we multiply top and bottom by 4 and we get
12/20
5*4=20 so we multiply top and bottom by 5 and we have
1(5/20)
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OpenStudy (alexandervonhumboldt2):
why *?
OpenStudy (alexandervonhumboldt2):
add
OpenStudy (peterg2001):
so the answer is 14 3/4?
OpenStudy (alexandervonhumboldt2):
i mdont know
OpenStudy (anonymous):
now 1=20/20 so we add that and we have\[\frac{ 40 }{ 20 }+\frac{ 12 }{ 20 }+\frac{ 25 }{ 20 }\]
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OpenStudy (alexandervonhumboldt2):
www.mathway.com try this
OpenStudy (anonymous):
this equals\[\frac{ 77 }{ 20 }\]
OpenStudy (anonymous):
20 goes into 77, 3 times, and we have a remainder of 17
OpenStudy (alexandervonhumboldt2):
your last fraction is wrong
OpenStudy (alexandervonhumboldt2):
11*5=55 not 25!!
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OpenStudy (anonymous):
it's not 11 in the original problem. It's 1
OpenStudy (anonymous):
it's\[1\frac{ 1 }{ 4 }\]
OpenStudy (alexandervonhumboldt2):
oh well then let me count
OpenStudy (alexandervonhumboldt2):
3 17/20