Question

Help please

Answer 1

alright so the first step you want is to get the top and bottom as individual fractions so lets look at just the top for now

Answer 2

\[\frac{ 7 }{ 3c }-6\]

Answer 3

we want them to have the same denominator so we multiply 6 by a form of one\[\frac{ 3c }{ 3c }\]
this makes them have the same denominator and allows us to combine them

Answer 4

\[\frac{ 7-18c }{ 3c }\]

Answer 5

do the same with the bottom

Answer 6

\[\frac{ 4 }{ c }+3\] multiply 3 by \[\frac{ c }{ c }\]\[\frac{ 4+3c }{ c }\]

Answer 7

so now what we have is \[\frac{ \frac{ 7-18c }{ 3c } }{ \frac{ 4+3c }{ c } }\]

Answer 8

now remember when you divide by a fraction you multiply by the reciprocal so this is the same as\[\frac{ 7-18c }{ 3c }*\frac{ c }{ 4+3c }\]

Answer 9

so we multiply those two terms

Answer 10

\[\frac{ 7c-18c ^{2} }{ 12c+9c ^{2} }\]

Answer 11

now we c *badum tss* that we can factor out a c and get\[\frac{ c*(7-18c) }{ c*(12+9c) }\]

Answer 12

the c we factored out will cancel and leave us with our answer

Answer 13

Thank you soo much!