Will give Medal and Fan. f(x)=(x^2+3x-4) and g(x)=(x+4). what is f*g and it's domain. What is f/g and it's domain.
@ganeshie8
@campbell_st
@uri
well if you write it out\[\frac{f(x)}{g(x)} = \frac{(x^2 + 3x -4)}{x - 4}\] you might like to factor the numerator.... and see if there are common factors.
Well the g(x)=x+4
opps yes the denominator should be (x + 4)
So I can remove one x correct?
no... factor the numerator..... can you do that...?
Well, -3 and -1
I suck at anything to do with factoring, so Helping me with this first part will be the hardest part I promise lol.
not quite... find the factors of -4 that add to 3.... the larger factor is positive and the smaller factor is negative.
so 4 and -1, yeah. I did it the opposit way and found things that add to -4 and multiply to 3.
so the numerator is (x + 4)(x -1) is there a common factor...?
4...?
well the common factor is (x + 4) which means f/g = (x - 1) so there are 2 options... the simplified verion has a domain of all real x. of if you look at the original problem x cannont be -4 as this gives a zero denominator. the point x = -4 in this case is a point of discontinuity so it depends on the level of math you are doing.... choices, all real x or all real x except x = -4
Okay. I understand, after the factoring incident lol. All real x except x=-4 is what i was looking for. Thank you.
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