Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Can you simplify the expression?

OpenStudy (anonymous):

OpenStudy (michele_laino):

please apply the distributive property of multiplication over addition

OpenStudy (michele_laino):

namely: \[\sqrt{6}*\sqrt{33}+\sqrt{6}*7\]

OpenStudy (michele_laino):

do you know how to multiply two radical each other?

OpenStudy (michele_laino):

oops ...two radicals each other?

OpenStudy (anonymous):

I'm sorry! I had to feed my nephew. @Michele_Laino I'm not sure...

OpenStudy (michele_laino):

for example we have: \[\sqrt{6}*\sqrt{33}=\sqrt{6*33}\] so please complete

OpenStudy (michele_laino):

6*33=...

OpenStudy (anonymous):

204

OpenStudy (michele_laino):

6*33=198 do you agree?

OpenStudy (anonymous):

Yes.

OpenStudy (michele_laino):

now note that 198=9*22, do you agree?

OpenStudy (anonymous):

Yes, I do.

OpenStudy (michele_laino):

perfect! So we can write: \[\sqrt{6}*\sqrt{33}=\sqrt{198}=\sqrt{9*22}=\sqrt{3^{2}*22}\] do you agree, please?

OpenStudy (michele_laino):

@Jonnychewy

OpenStudy (anonymous):

Sounds good to me. =)

OpenStudy (michele_laino):

ok! please note that the exponent of 3 is 2, so we can take out it of the root sign,

OpenStudy (michele_laino):

and we can write: \[\sqrt{3*22}=3*\sqrt{22}\] is it right for you?

OpenStudy (anonymous):

Yes.

OpenStudy (michele_laino):

oops sorry: \[\sqrt{3^{2}*22}=3*\sqrt{22}\]

OpenStudy (michele_laino):

it has been sufficient divide the exponent of 3^2, by 2

OpenStudy (michele_laino):

namely 2/2=1 and 1 is the new exponent of 3 when it is out of square root

OpenStudy (michele_laino):

so your expression is simplified as below: \[3\sqrt{22}+7\sqrt{6}\] that's all

OpenStudy (anonymous):

Wow! Okay, that's what I was thinking too. Thank you!

OpenStudy (michele_laino):

Thank you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!