Mathematics
7 Online
OpenStudy (anonymous):
Can you simplify the expression?
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OpenStudy (anonymous):
OpenStudy (michele_laino):
please apply the distributive property of multiplication over addition
OpenStudy (michele_laino):
namely:
\[\sqrt{6}*\sqrt{33}+\sqrt{6}*7\]
OpenStudy (michele_laino):
do you know how to multiply two radical each other?
OpenStudy (michele_laino):
oops ...two radicals each other?
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OpenStudy (anonymous):
I'm sorry! I had to feed my nephew. @Michele_Laino I'm not sure...
OpenStudy (michele_laino):
for example we have:
\[\sqrt{6}*\sqrt{33}=\sqrt{6*33}\]
so please complete
OpenStudy (michele_laino):
6*33=...
OpenStudy (anonymous):
204
OpenStudy (michele_laino):
6*33=198 do you agree?
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OpenStudy (anonymous):
Yes.
OpenStudy (michele_laino):
now note that 198=9*22, do you agree?
OpenStudy (anonymous):
Yes, I do.
OpenStudy (michele_laino):
perfect! So we can write:
\[\sqrt{6}*\sqrt{33}=\sqrt{198}=\sqrt{9*22}=\sqrt{3^{2}*22}\]
do you agree, please?
OpenStudy (michele_laino):
@Jonnychewy
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OpenStudy (anonymous):
Sounds good to me. =)
OpenStudy (michele_laino):
ok! please note that the exponent of 3 is 2, so we can take out it of the root sign,
OpenStudy (michele_laino):
and we can write:
\[\sqrt{3*22}=3*\sqrt{22}\]
is it right for you?
OpenStudy (anonymous):
Yes.
OpenStudy (michele_laino):
oops sorry:
\[\sqrt{3^{2}*22}=3*\sqrt{22}\]
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OpenStudy (michele_laino):
it has been sufficient divide the exponent of 3^2, by 2
OpenStudy (michele_laino):
namely 2/2=1 and 1 is the new exponent of 3 when it is out of square root
OpenStudy (michele_laino):
so your expression is simplified as below:
\[3\sqrt{22}+7\sqrt{6}\]
that's all
OpenStudy (anonymous):
Wow! Okay, that's what I was thinking too. Thank you!
OpenStudy (michele_laino):
Thank you!