Question

Can someone explain me how to do this

GPA % of Juniors
0.00 – 1.99 16%
2.00 – 2.49 24%
2.50 – 2.99 28%
3.00 – 3.49 22%
3.50 – 4.00 10%


Referring to the data above, find the probability that a randomly selected junior's GPA is in the 2.50 - 3.49 range, given that it is greater than 1.99.

the answer should be .676

Answer 1

if assume that X is the height;
P(2.50<X<3.49 | X>1.99) = P( 2.50<X<3.49 intersection X>1.99)/P(X>1.99)
the intersection is :-

Answer 2

P( 2.50<X<3.49 intersection X>1.99)= > P( 2.50<X<3.49 )

Answer 3

this is the new one
P( 2.50<X<3.49 )/ P(X>1.99) = (50/100)/(84/100) = 0.5952 this is the answer