plutonium -240 decays according to the function Q(t)=Qoe^-kt
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OpenStudy (anonymous):
OpenStudy (danjs):
k = 0.00011
Qo = 36 grams
Q(t) = 12 grams
Find t
OpenStudy (danjs):
\[12 = 36 e ^{-0.00011*t}\]
OpenStudy (danjs):
\[\ln \frac{ 12 }{ 36 } = -.00011*t\]
OpenStudy (danjs):
u have it from there?
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OpenStudy (anonymous):
A?
OpenStudy (danjs):
oh i didnt calculate,, one sec
OpenStudy (danjs):
9987.38
OpenStudy (danjs):
D
OpenStudy (anonymous):
could you help me with one more?
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OpenStudy (danjs):
sure
OpenStudy (anonymous):
OpenStudy (anonymous):
Please, thank you!!
OpenStudy (danjs):
ok we have to test each one
OpenStudy (danjs):
\[P(t) = 64 / [1 + 11e ^{-0.08t}]\]
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OpenStudy (danjs):
t = years since 1990
P(t) = Billions of People
OpenStudy (danjs):
In 1990 there were 5.33 billion people? t = 0
5.33 = 64 / [1+11e^-0.08(0)]
OpenStudy (danjs):
recall e^0 = 1
5.33 = 64 / 12 TRUE
OpenStudy (danjs):
B is also True
OpenStudy (danjs):
Because e^-x starts out Huge for small values, then approaches zero as you go off to larger numbers, the denominator will go to 1,
the population will approach 64 billion at large times
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OpenStudy (anonymous):
could A & C also true?
OpenStudy (danjs):
c is not true, the carrying capacity is 64 billion