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Mathematics 7 Online
OpenStudy (anonymous):

HELP WITH Probability There are 5 questions on a multiple choice exam, each with five possible answers. If a student guesses on all five questions, what is the probability the student gets one question correct? Express your answer as a percent rounded to the nearest tenth. 41.0% 25.1% 20.5% 28.7%

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

k

OpenStudy (anonymous):

@FibonacciChick666

OpenStudy (fibonaccichick666):

what's the chance for the first one?

OpenStudy (anonymous):

.2 I think,

OpenStudy (fibonaccichick666):

use a fraction, life is easier

OpenStudy (fibonaccichick666):

ok, then how about the second one? Whats the chance of getting it right?

OpenStudy (anonymous):

the chance of getting it right is 0.2, getting it wrong is 0.8

OpenStudy (anonymous):

@FibonacciChick666

OpenStudy (fibonaccichick666):

ok, so are they all a 1 in 5 chance?

OpenStudy (fibonaccichick666):

by themselves that is

OpenStudy (mathmate):

"the chance of getting it right is 0.2, getting it wrong is 0.8" That is correct for answering one question. This is the probability of success (p=0.2) in a Bernoulli trial (either right or wrong, no other results). When there are n trials with the same probability of success, and each trial is independent of each other, you could use the binomial distribution, which gives the probability of r successes in n trials: \(P(r)=\frac{n!}{n-r!\ r!}p^r(1-p)^{n-r}\) Take out your calculator and find the answer. Here n=5, p=0.2, r=1.

OpenStudy (anonymous):

41% @mathmate

OpenStudy (mathmate):

That is correct! Good job! :)

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