i will give you a medal if you help me and i will fan you
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OpenStudy (anonymous):
what is the answer to \[\sqrt{41}\] =
\[\sqrt{c^2}\]
OpenStudy (anonymous):
the answer chooses are
6.4
7.3
8.2
9.1
OpenStudy (anonymous):
So you're solving for c?
\[\sqrt{c^2} = \sqrt{41}\] look at the the squareroot cancels the square out on the left side, so with that said, your answer is?
OpenStudy (anonymous):
i am very confused
OpenStudy (anonymous):
\[\sqrt{c^2} \implies c^{2/2} = c\]
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OpenStudy (anonymous):
\[\huge \sqrt[m]{x^n} \implies x^{n/m}\]
OpenStudy (anonymous):
no you salving for \[\sqrt{41}\]
OpenStudy (anonymous):
\[c = \sqrt{41}\] that's it, you solved for c.
OpenStudy (anonymous):
Just plug \[\sqrt{41}\] into a calculator, prob around 6
OpenStudy (anonymous):
answer = 6.03
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OpenStudy (anonymous):
Do you understand though?
OpenStudy (anonymous):
the awnser is not 6.3
OpenStudy (anonymous):
It should be 6.4
OpenStudy (anonymous):
ya i know thank you
OpenStudy (anonymous):
can you help me with 1 more
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OpenStudy (anonymous):
Sure, but I have to go in a minute, so hopefully it's quick :P
OpenStudy (anonymous):
What is the distance from (−2, 4) to (0, −6)? Round your answer to the nearest hundredth.
9.23
10.20
10.98
11.34
OpenStudy (anonymous):
You can use the distance formula here: \[d = \sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}} \]
your points being \[(x_1,y_1),(x_2,y_2)\]
OpenStudy (anonymous):
Sorry, I have to go now, good luck!
OpenStudy (anonymous):
@ShawnSpencer i am terribly sorry i meant 6.403 my apolagies
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OpenStudy (anonymous):
i still dont under stand
this one
OpenStudy (anonymous):
@ShawnSpencer do you see the formula that iambatman has given to you
OpenStudy (anonymous):
i got it 10.20
OpenStudy (anonymous):
thank you any way
OpenStudy (anonymous):
@johnson464
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OpenStudy (anonymous):
\[6^2+2.2^2=c^2\]
OpenStudy (anonymous):
plz help me on this one
OpenStudy (anonymous):
one sec
OpenStudy (anonymous):
\[36+2.2=C^2\]
OpenStudy (anonymous):
\[40.84=c^2\]
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OpenStudy (anonymous):
\[\sqrt{40.84}=\sqrt{c^2}\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
the thing that you can choose out of are
10
12
13
15
OpenStudy (anonymous):
plz help
OpenStudy (anonymous):
ok im working it out
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OpenStudy (anonymous):
oh sorry
OpenStudy (carlosjose):
12
OpenStudy (anonymous):
ok thanks
OpenStudy (carlosjose):
:)
OpenStudy (anonymous):
that was Wrong
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