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Mathematics 22 Online
OpenStudy (anonymous):

i will give you a medal if you help me and i will fan you

OpenStudy (anonymous):

what is the answer to \[\sqrt{41}\] = \[\sqrt{c^2}\]

OpenStudy (anonymous):

the answer chooses are 6.4 7.3 8.2 9.1

OpenStudy (anonymous):

So you're solving for c? \[\sqrt{c^2} = \sqrt{41}\] look at the the squareroot cancels the square out on the left side, so with that said, your answer is?

OpenStudy (anonymous):

i am very confused

OpenStudy (anonymous):

\[\sqrt{c^2} \implies c^{2/2} = c\]

OpenStudy (anonymous):

\[\huge \sqrt[m]{x^n} \implies x^{n/m}\]

OpenStudy (anonymous):

no you salving for \[\sqrt{41}\]

OpenStudy (anonymous):

\[c = \sqrt{41}\] that's it, you solved for c.

OpenStudy (anonymous):

Just plug \[\sqrt{41}\] into a calculator, prob around 6

OpenStudy (anonymous):

answer = 6.03

OpenStudy (anonymous):

Do you understand though?

OpenStudy (anonymous):

the awnser is not 6.3

OpenStudy (anonymous):

It should be 6.4

OpenStudy (anonymous):

ya i know thank you

OpenStudy (anonymous):

can you help me with 1 more

OpenStudy (anonymous):

Sure, but I have to go in a minute, so hopefully it's quick :P

OpenStudy (anonymous):

What is the distance from (−2, 4) to (0, −6)? Round your answer to the nearest hundredth. 9.23 10.20 10.98 11.34

OpenStudy (anonymous):

You can use the distance formula here: \[d = \sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}} \] your points being \[(x_1,y_1),(x_2,y_2)\]

OpenStudy (anonymous):

Sorry, I have to go now, good luck!

OpenStudy (anonymous):

@ShawnSpencer i am terribly sorry i meant 6.403 my apolagies

OpenStudy (anonymous):

i still dont under stand this one

OpenStudy (anonymous):

@ShawnSpencer do you see the formula that iambatman has given to you

OpenStudy (anonymous):

i got it 10.20

OpenStudy (anonymous):

thank you any way

OpenStudy (anonymous):

@johnson464

OpenStudy (anonymous):

\[6^2+2.2^2=c^2\]

OpenStudy (anonymous):

plz help me on this one

OpenStudy (anonymous):

one sec

OpenStudy (anonymous):

\[36+2.2=C^2\]

OpenStudy (anonymous):

\[40.84=c^2\]

OpenStudy (anonymous):

\[\sqrt{40.84}=\sqrt{c^2}\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

the thing that you can choose out of are 10 12 13 15

OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

ok im working it out

OpenStudy (anonymous):

oh sorry

OpenStudy (carlosjose):

12

OpenStudy (anonymous):

ok thanks

OpenStudy (carlosjose):

:)

OpenStudy (anonymous):

that was Wrong

OpenStudy (anonymous):

:(

OpenStudy (carlosjose):

oh sorry i did it wrong

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