Question

Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseburgers in the first hour of business. Let x represent the number of hamburgers and y represent the number of cheeseburgers. The inequality 2.50x + 3.50y ≤ 30 represents the food sales in the first hour.

If Ben has sold 4 cheeseburgers, what is the maximum value of hamburgers Ben could have sold?

Answer 1

@Secret-Ninja , @iGreen

Answer 2

@iambatman

Answer 3

@ganeshie8

Answer 4

Okay, first, you have to change the variable for the cheeseburgers (y) to 4 because he sold 4. You now have:
2.50x + 3.50 x 4 <= 30

So now you just solve for x.

\[ 2.50x + 3.50 \times 4 <= 30\]\[2.50x + 14 <= 30 \]\[2.50x <= 30 - 14 \]\[2.50x <= 16 \]\[2.50 \div x \le 16\]

Answer 5

Now you move the 2.50 to the other side and divide it into 16.
\[x \le 16 \div 2.50\]
\[x \le 6.4\]

Answer 6

And you can't sell .4 of a burger, so he sold 6 hamburgers.

Answer 7

I hope that this helped. @iam.dhue

Answer 8

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