What is the solution to the system of equations represented by the two equations? y=3/2x y=-1/2x+4 (???,???)
@shinebrightlikeadimon
give me a sec
Ok same i gotta help some one
I'm back ^_^
Not that it matters xD
@mathmate I'm kinda lost could you help?
I am equally lost. Not sure what problem you are trying to solve!
Me either! xD
One moment brb i was tagged
y=3/2x y=-1/2x+4 could mean a linear system of equations: \(y=\frac{3}{2}x\) \(y=-\frac{1}{2}x+4\) or a different system of linear equations: \(y=\frac{3}{2x}\) \(y=-\frac{1}{2x}+4\)
Ok nooow that i know that lol what can i do to solve this?
or even \(y=-\frac{1}{2x}+4\) \(y=-\frac{1}{2x+4}\)
One sec brb
Your lack of parentheses makes your question ambiguous. All fractions have implicit parentheses for each of numerator and denominator.
Thats what the ? is one second let me look at it again
@mathmate
@Fransisco_w
I tagged him to see if he knew what to do
It would not be ambiguous if you wrote y=(3/2)x y=-(1/2)x+4 Whenever you have y= and y= for both equations, just equate the right hand sides and solve for x. In this case, (3/2)x=-(1/2)x+4 and solve for x. After that, substitute the value of x into either equation and solve for y.
So then would it be (3,2)
Or no I think it would be (2,3)
Ok, yes. I thought you put them backwards! Good, well done!
(2,3) is right.
Yay!
:)
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