A rocket engine, 2.39 cross product 10^−5 watts/cm^2

Question

anonymous · Answer

dB=10log[I/(10^-12)] 

Not much to do here, just plug in the value for I (intensity). 

First we have to convert from W/cm^2 to W/m^2. Just multiply it by 100^2, because there are 100^2 cm^2/m^2 

dB=10log[(.266)/(10^-12)] 

=10log(2.66e11) 

=114 dB

anonymous · Answer

hold on...I messed up with something

anonymous · Answer

dB=10log(I/I0) 

=10log(2.46∗10−1/10−12) 

=10log(2.46∗1011)=113.91dB−−−−−−−−−ans

anonymous · Answer

A rocket engine, 2.39 cross 10−5watts/cm2

anonymous · Answer

Hold on..even I'm confused now...I'm going to ask @Catlover5925 for help

anonymous · Answer

@roneal I asked her for help..hold on

catlover5925 · Answer

idk, these are hard questions i dont understand what you are doing here