Question

A rocket engine, 2.39 cross product 10^−5 watts/cm^2

Answer 1

dB=10log[I/(10^-12)]

Not much to do here, just plug in the value for I (intensity).

First we have to convert from W/cm^2 to W/m^2. Just multiply it by 100^2, because there are 100^2 cm^2/m^2

dB=10log[(.266)/(10^-12)]

=10log(2.66e11)

=114 dB

Answer 2

hold on...I messed up with something

Answer 3

dB=10log(I/I0)

=10log(2.46∗10−1/10−12)

=10log(2.46∗1011)=113.91dB−−−−−−−−−ans

Answer 4

A rocket engine, 2.39 cross 10−5watts/cm2

Answer 5

Hold on..even I'm confused now...I'm going to ask @Catlover5925 for help

Answer 6

@roneal I asked her for help..hold on

Answer 7

idk, these are hard questions i dont understand what you are doing here