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OpenStudy (anonymous):
putting the question up one sec
OpenStudy (anonymous):
\[f(x)=4x-2 \]
\[g(x)=x+1\]
OpenStudy (anonymous):
i need to figure out both f(g(x)) and g(f(x))
OpenStudy (anonymous):
(g o f )(1) = g( f (1))
= g(2( ) + 3) ... setting up to insert the original input
= g(2(1) + 3)
= g(2 + 3)
= g(5)
= –( )2 + 5 ... setting up to insert the new input
= –(5)2 + 5
= –25 + 5
= –20
OpenStudy (anonymous):
so negotive 20 maybe?
thats what i would put
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OpenStudy (anonymous):
actually i would put 11
OpenStudy (anonymous):
it wouldnt be an exact number. i know that much. I'm basically simplifying because i dont know what the x value is
OpenStudy (anonymous):
i just dont know how to simplify it
OpenStudy (anonymous):
its also 2 different problems so there would be two answers not one
OpenStudy (math&ing001):
To find f(g(x)) simply replace the x in f(x) with the expression of g(x) like this:
f(g(x)) = 4(x+1) - 2 = 4x +4 -2 = 4x +2
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OpenStudy (anonymous):
fx=4x-2
and
gx=x+1
OpenStudy (math&ing001):
It's the same for g(f(x)),
g(f(x)) = (4x-2) + 1
OpenStudy (anonymous):
mmmk i know what i did wrong i didnt simplify it all the way thank you @math&ing001