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Mathematics 16 Online
OpenStudy (anonymous):

need help please will medal

OpenStudy (anonymous):

putting the question up one sec

OpenStudy (anonymous):

\[f(x)=4x-2 \] \[g(x)=x+1\]

OpenStudy (anonymous):

i need to figure out both f(g(x)) and g(f(x))

OpenStudy (anonymous):

(g o f )(1) = g( f (1)) = g(2( ) + 3) ... setting up to insert the original input = g(2(1) + 3) = g(2 + 3) = g(5) = –( )2 + 5 ... setting up to insert the new input = –(5)2 + 5 = –25 + 5 = –20

OpenStudy (anonymous):

so negotive 20 maybe? thats what i would put

OpenStudy (anonymous):

actually i would put 11

OpenStudy (anonymous):

it wouldnt be an exact number. i know that much. I'm basically simplifying because i dont know what the x value is

OpenStudy (anonymous):

i just dont know how to simplify it

OpenStudy (anonymous):

its also 2 different problems so there would be two answers not one

OpenStudy (math&ing001):

To find f(g(x)) simply replace the x in f(x) with the expression of g(x) like this: f(g(x)) = 4(x+1) - 2 = 4x +4 -2 = 4x +2

OpenStudy (anonymous):

fx=4x-2 and gx=x+1

OpenStudy (math&ing001):

It's the same for g(f(x)), g(f(x)) = (4x-2) + 1

OpenStudy (anonymous):

mmmk i know what i did wrong i didnt simplify it all the way thank you @math&ing001

OpenStudy (math&ing001):

Welcome !

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