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Simplify the rational expression. State any excluded values.
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As a start : factor the denominator
I'm not sure how =/
in the denominator you have \(-5x + x^2\)
it has two terms and \(x\) is common in them so pull it out : \[-5x+x^2 = x(-5+x)\]
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Alight.
Please excuse my stupidity.... but is this the answer?
@ganeshie8
right, what about the excluded values ?
\[\dfrac{2x}{-5x+x^2} = \dfrac{2}{x(-5+x)} = \dfrac{2}{x-5},~~x\ne 0, 5\]
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where x 5,0
Wow ! Thank you! =)
@ganeshie8
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