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OpenStudy (anonymous):
Find the indicated limit, if it exists.
limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and f of x equals 9 minus x when x is greater than or equal to 9
The answers are:
18
0
9
The limit does not exist.
I think the limit is 18. Am I right?
9 years ago
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OpenStudy (freckles):
\[\lim_{x \rightarrow 9-}(x+9) \\ \lim_{x \rightarrow 9^+}(9-x)\]?
9 years ago
OpenStudy (anonymous):
This is how it looks
9 years ago
OpenStudy (freckles):
oh ok
9 years ago
OpenStudy (freckles):
we you need to find left and right limit
9 years ago
OpenStudy (freckles):
that is plug in 9 for both functions on the sides of x=9
9 years ago
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OpenStudy (freckles):
if they equal, the the limit exist
9 years ago
OpenStudy (anonymous):
correct
9 years ago
OpenStudy (freckles):
if they don't equal, then the limit doesn't exist
9 years ago
OpenStudy (anonymous):
9 + 9 = 18
27 - 9 = 18
So the limit is 18?
@freckles
9 years ago
OpenStudy (freckles):
sounds fab
9 years ago
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OpenStudy (anonymous):
Could you help with another?
9 years ago
OpenStudy (anonymous):
Thank you by the way!
9 years ago
OpenStudy (freckles):
sure what is it
9 years ago
OpenStudy (anonymous):
The answers are 1.3
-1
4
5
I think it's 1.3. Is that right?
9 years ago
OpenStudy (anonymous):
Find limit as x approaches two from the left of f of x.
9 years ago
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OpenStudy (freckles):
so you are saying 1.3 because it looks like that hols is above y=1
9 years ago
OpenStudy (freckles):
and yes that looks about right then
9 years ago
OpenStudy (freckles):
gj
9 years ago
OpenStudy (anonymous):
Basically.
9 years ago
OpenStudy (freckles):
|dw:1418321402372:dw|
yeah basically we are only curious about the left hand side of x=2
(and also we don't even care what happens at x=2)
9 years ago
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