Find the indicated limit, if it exists.
limit of f of x as x approaches 1 where f of x equals 1 minus x when x is less than 1, 8 when x equals 1, and x plus 7 when x is greater than 1
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OpenStudy (chosenmatt):
what do you think?
OpenStudy (anonymous):
The answers are:
8
0
7
The limit does not exist.
I think the answer is 8. Is that correct?
OpenStudy (anonymous):
@freckles
OpenStudy (xapproachesinfinity):
hmmm just take the limit to the right of 1 and also limit to the left of 1
OpenStudy (xapproachesinfinity):
and then compare if they are equal
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OpenStudy (chosenmatt):
good job @xapproachesinfinity @sunshine201
OpenStudy (xapproachesinfinity):
so first start with \(\large \lim_{x\to1^{+}}f(x)=\lim_{x\to1^{+}}x+7=?\)
OpenStudy (anonymous):
8?
OpenStudy (xapproachesinfinity):
correct! how about the left
OpenStudy (anonymous):
Is that the one that's 1 - x?
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OpenStudy (xapproachesinfinity):
yes x<1 means we are taking number to the left of 1
OpenStudy (anonymous):
so 1 - 8 = -7?
OpenStudy (xapproachesinfinity):
hmmm no
we are doing the limit to the left of 1
OpenStudy (xapproachesinfinity):
so you have to evaluate 1 not 8
OpenStudy (xapproachesinfinity):
\(\large \lim_{x\to1^{-}}1-x=?\)
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OpenStudy (anonymous):
1 - 1 = 0?
OpenStudy (xapproachesinfinity):
you got it?
OpenStudy (anonymous):
The limit is 0?
OpenStudy (xapproachesinfinity):
yes correct! now is this true \(\large \lim_{x\to1^{+}}f(x)=\lim_{x\to1^{-}}f(x)\)
OpenStudy (xapproachesinfinity):
for the limit to exist the two limits must equal
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OpenStudy (xapproachesinfinity):
we are looking for the limit as x goes to 1
so we need to test the limit from the right and the limit from the left of 1
and then compare
OpenStudy (xapproachesinfinity):
limit from the right is 8
limit from the left is 0
what can you say