Mason and Nora decided to swim across the river. Mason began swimming 33 seconds earlier than Nora. Mason swam at a speed of 3 feet per second. Nora swam at a speed of 4 feet per second. For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?
i forget what the formula is to this
i have no clue.
yeah i took something like this a year ago but it totally slipped my mind let me look. what is the lesson you are on?
so that i know like what to search
@Starbucks
its algebra , but like im in the end so i dont really know..
ok well what is it asking for?
For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?
i know that nora caught up to mason at 120 seconds, but that was wrong.
ok one sec
@SolomonZelman
that guy i bet can help
i hoope.
@deliciotron
@chosenmatt
speed = distance / time but once we have the equation, we can use any of its variations, speed = distance / time distance = speed * time time = distance / speed
that's it. that's the equation
For example, suppose we drive for 2 hours at 30 miles per hour, for a total of 60 miles. If we know the time and the speed, we can find the distance: 2 hours * 30 miles/hour = 60 miles If we know the time and the distance, we can find the speed: 60 miles / 2 hours = 30 miles/hour If we know the speed and the distance, we can find the time: 60 miles / (30 miles/hour) = 2 hours It's a little like having a family of multiplication facts, e.g., 12 = 3 * 4 3 = 12 / 4 4 = 12 / 3
i dont get how to use that for my question though .
Just forgot. lemme think for a sec
Does it tell you howw long it took them to be at the same place?
nope.
i got that myself though, it took 120 seconds.
Ok, so 120 seconds times 4 feet per second and 120 seconds times 3 feet per second. That would be the next step.
Actually it would be 4 feet per second * 120 second and the same for 3 feeet per second
feet*
@kobeni-chan
Then you see how long it takes for nora to pass mason
Did that help?
no .
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