sec(2/pi-x)=cscx
this is not an identity.
And you sure you mean 2/pi, and not the other way, --- pi/2 ?
that's what it says on my homework
I'm supposed to use a difference formula and algebra
\(\large\color{black}{\sec(\frac{2}{\pi}-x)=\csc x }\) it is this?
no my problem says pi divided by two
\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\)
yes
\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\) is an identity.
firstly I would like to thank you for your time. but I am confused on what to do with the problem
what's wrong with this site, connection snapps all day.
\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\) \(\LARGE\color{black}{\frac{1}{\cos(\frac{\pi}{2}-x)}=\frac{1}{\sin x} }\) \(\LARGE\color{black}{\cos(\frac{\pi}{2}-x)=\sin x}\)
then use a formula, \(\large\color{black}{\cos(a-b) =\cos(a)\cos(b)+\sin(a)\sin(b)}\)
if you have any questions, let me know. And this is not a problem, I am here to attempt to help people out.
okay thank you
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