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Mathematics 7 Online
OpenStudy (anonymous):

sec(2/pi-x)=cscx

OpenStudy (solomonzelman):

this is not an identity.

OpenStudy (solomonzelman):

And you sure you mean 2/pi, and not the other way, --- pi/2 ?

OpenStudy (anonymous):

that's what it says on my homework

OpenStudy (anonymous):

I'm supposed to use a difference formula and algebra

OpenStudy (solomonzelman):

\(\large\color{black}{\sec(\frac{2}{\pi}-x)=\csc x }\) it is this?

OpenStudy (anonymous):

no my problem says pi divided by two

OpenStudy (solomonzelman):

\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\)

OpenStudy (anonymous):

yes

OpenStudy (solomonzelman):

\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\) is an identity.

OpenStudy (anonymous):

firstly I would like to thank you for your time. but I am confused on what to do with the problem

OpenStudy (solomonzelman):

what's wrong with this site, connection snapps all day.

OpenStudy (solomonzelman):

\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\) \(\LARGE\color{black}{\frac{1}{\cos(\frac{\pi}{2}-x)}=\frac{1}{\sin x} }\) \(\LARGE\color{black}{\cos(\frac{\pi}{2}-x)=\sin x}\)

OpenStudy (solomonzelman):

then use a formula, \(\large\color{black}{\cos(a-b) =\cos(a)\cos(b)+\sin(a)\sin(b)}\)

OpenStudy (solomonzelman):

if you have any questions, let me know. And this is not a problem, I am here to attempt to help people out.

OpenStudy (anonymous):

okay thank you

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