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OpenStudy (anonymous):
sec(2/pi-x)=cscx
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OpenStudy (solomonzelman):
this is not an identity.
OpenStudy (solomonzelman):
And you sure you mean 2/pi, and not the other way, --- pi/2 ?
OpenStudy (anonymous):
that's what it says on my homework
OpenStudy (anonymous):
I'm supposed to use a difference formula and algebra
OpenStudy (solomonzelman):
\(\large\color{black}{\sec(\frac{2}{\pi}-x)=\csc x }\) it is this?
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OpenStudy (anonymous):
no my problem says pi divided by two
OpenStudy (solomonzelman):
\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\)
OpenStudy (anonymous):
yes
OpenStudy (solomonzelman):
\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\)
is an identity.
OpenStudy (anonymous):
firstly I would like to thank you for your time. but I am confused on what to do with the problem
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OpenStudy (solomonzelman):
what's wrong with this site, connection snapps all day.
OpenStudy (solomonzelman):
\(\Large\color{black}{\sec(\frac{\pi}{2}-x)=\csc x }\)
\(\LARGE\color{black}{\frac{1}{\cos(\frac{\pi}{2}-x)}=\frac{1}{\sin x} }\)
\(\LARGE\color{black}{\cos(\frac{\pi}{2}-x)=\sin x}\)
OpenStudy (solomonzelman):
then use a formula, \(\large\color{black}{\cos(a-b) =\cos(a)\cos(b)+\sin(a)\sin(b)}\)
OpenStudy (solomonzelman):
if you have any questions, let me know. And this is not a problem, I am here to attempt to help people out.
OpenStudy (anonymous):
okay thank you
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