Question

Log9 x=3

Answer 1

Take both sides to be exponents of \(9\).

Answer 2

\(\Large\color{black}{\log_{\color{red}{a} }\color{green}{b}=\color{blue}{c}~~~~~~~~\Longrightarrow~~~~~~~~\color{green}{b}=\color{red}{a}^\color{blue}{c}}\)

Answer 3

\[
9^{\log_9 x} = 9^3\implies x=9^3
\]

Answer 4

How

Answer 5

hey, can you tell me what x is in this expression \(\Large\color{black}{\log_{\color{red}{9} }\color{green}{x}=\color{blue}{3}}\) ?

just apply the rule:
\(\Large\color{black}{\log_{\color{red}{a} }\color{green}{b}=\color{blue}{c}~~~~~~~~\Longrightarrow~~~~~~~~\color{green}{b}=\color{red}{a}^\color{blue}{c}}\)

Answer 6

I really don't get this😩

Answer 7

okay, lets do a couple of example.
when we have,
\(\Large\color{black}{\log_{\color{red}{4} }\color{green}{x}=\color{blue}{2}}\)
when we apply our rule,
\(\Large\color{black}{\log_{\color{red}{4} }\color{green}{x}=\color{blue}{2}~~~~~~~~\Longrightarrow~~~~~~~~\color{green}{x}=\color{red}{4}^\color{blue}{2}=16}\)

Answer 8

I don't have time for examples time is running

Answer 9

And another one,
lets say you have, \(\Large\color{black}{\log_{\color{red}{2} }\color{green}{w}=\color{blue}{3}}\)

then we apply our rule, again,

\(\Large\color{black}{\log_{\color{red}{2} }\color{green}{w}=\color{blue}{3}~~~~~~~~\Longrightarrow~~~~~~~~\color{green}{w}=\color{red}{2}^\color{blue}{3}=8}\)

Answer 10

you are taking a timed test?

Answer 11

It's a timed assignment I'm trying to graduate

Answer 12

but I think I can fairly say that my explanation is clear.
And just swabbing answers is not going to get you anywhere.

Answer 13

Thank you for your help

Answer 14

helped?

Answer 15

😩😩😩😩😩😩

Answer 16

so you understand?

Answer 17

No not really

Answer 18

\[
\log_{\color{red}9}x = 3
\]We just look at the base of the logarithm. In this case, it is \(9\). We take \(9\) to the power of each side. It is that simple.

If we had \[
\log_{4} x= 6
\]We would take both sides as exponents of \(4\). \[
4^{\log_4x}=4^6
\]The rule is that \(a^{\log_a x} = x\).