Question

Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4).

y = four thirdsx + 8
y = four thirdsx + 3
y = -three fourthsx + 8
y = -three fourthsx + 3

@AriPotta

Answer 1

ok first convert 4x - 3y = -12 into slope-intercept form

Answer 2

Slope intercept form is \[y=mx+b\]

Answer 3

I don't know how :(

Answer 4

ok so putting it in slope-intercept form is basically solving for y. so we want y by itself. first, we're going to subtract 4x from both sides

-3y = -4x - 12

then divide both sides by -3 to get
y = 4/3x + 4

Answer 5

parallel lines have the same slope

Answer 6

so since we know the slope of the line, and a point the line goes through, (-3,4), we can use the point-slope form: y - y1 = m(x - x1)

Answer 7

so we're going to plug the info into the formula:

y - 4 = 4/3(x + 3)

Answer 8

then we have to convert it into slope-intercept form

y - 4 = 4/3(x + 3)
y - 4 = 4/3x + 4
y = 4/3x + 8

Answer 9

make sense?

Answer 10

kinda yeah

Answer 11

ok cool :)

Answer 12

do you have any questions?

Answer 13

thats it, thank you

Answer 14

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